Ratio of the area of ∆WXY to the area of ∆WZY is 3 : 4 (Fig. 9.33). If the area of ∆WXZ is 56 cm2 and WY = 8 cm, find the lengths of XY and YZ.

We know that, area of a triangle =
× b × h
Given, Area of ∆WXZ = 56 cm2
× XZ × 8 = 56
XZ =
= 14 cm
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4XY = 42 – 3XY
7XY = 42
XY = 6 cm
YZ = XZ – XY = 14 – 6 = 8 cm
So, XY = 6 cm and YZ = 8 cm
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