Q91 of 131 Page 226

In Fig. 9.44 a rectangle with perimeter 264 cm is divided into five congruent rectangles. Find the perimeter of one of the rectangles.

Since the rectangles are congruent, their length and breadth are equal.



Given, Perimeter of the rectangle = 264 cm


It can be observed from the figure that


4l + 5b = 264


And 2l = 3b


On solving the above equations:


11b = 264


b = 24 cm


l = × 24 = 36 cm


Hence, perimeter of smaller rectangles = 2 × (l + b) = 2 × (36 + 24) = 120 cm


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