In Fig. 9.44 a rectangle with perimeter 264 cm is divided into five congruent rectangles. Find the perimeter of one of the rectangles.

Since the rectangles are congruent, their length and breadth are equal.

Given, Perimeter of the rectangle = 264 cm
It can be observed from the figure that
4l + 5b = 264
And 2l = 3b
On solving the above equations:
11b = 264
⇒ b = 24 cm
∴ l =
× 24 = 36 cm
Hence, perimeter of smaller rectangles = 2 × (l + b) = 2 × (36 + 24) = 120 cm
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