Q16 of 131 Page 226

In Fig. 9.21, if PR = 12 cm, QR = 6 cm and PL = 8 cm, then QM is

Given that, PR = 12cm, QR = 6cm and PL = 8cm


Now in right angled PLR, using Pythagoras theorem,




= -


=


= 144- 64


= 80


4


LQ + QR


LQ = LR-QR


LQ = 4


Area of PLR = ×PL


= 4×8


= 16 cm2


Area of PLQ = ×PL


= 4×8


= 4(4


= 16 cm2


Area of PLR = Area of PLQ + Area of PQR


16 = (16 + Area of PQR


Area of PQR = 24 cm2


×QM = 24


×QM = 24


4cm

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