Q1 of 56 Page 119

Point D and E lie on the sides AB and AC respectively of ΔABC such that DE|| BC. Then,

If AD = 4x – 3, AE = 8x – 7, BD = 3x – 1 and CE = 5x – 3, then find the value of x.


Given,


AD = 4x – 3


BD = 3x – 1


AE = 8x – 7


CE = 5x – 3


In ΔABC,


∵DE|| BC


∴|(By Thales Theorem)






⇒ 20x2 – 27x + 9 = 24x2 – 29x + 7


⇒ 4x2 – 2x – 2 = 0


⇒ x = 1, – 1/2


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