Q9 of 56 Page 127

In figure PQ and RS are parallel. Then prove that ΔPOQ ~ ΔSOR.


Given,


PQ||RS


In ΔPOQ & ΔSOR,


⇒ ∠PQO = ∠ORS |Alternate angles


⇒ ∠QPO = ∠OSR |Alternate angles


⇒ ∠POQ = ∠ROS |Vertically opposite angles


Thus, ΔPOQ~ΔSOR by AAA Similarity Rule


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