Q3 of 56 Page 119

In the given figure points L, M and N respectively lie on OA, OB and OC such that LM || AB and MN || BC. Then, show that LN || AC.

In OAB & OLM


LM||AB


…(1) |By Basic Proportionality Theorem(BPT)


In ΔOMN & ΔOBC,


MN||BC


…(2) |By BPT


From (1)&(2)


…(3)


In ΔOLN & ΔOAC



⇒ LN||AC by Converse of BPT


Hence, proved.


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