Q13 of 56 Page 127

Prove that the triangles formed by joining the mid – points of the three sides of a triangle consecutively are similar to their original triangle.

Let there be a ΔABC with the mid points D,E and F of sides AB, AC and BC.



In ΔADE and ΔABC,



D is the mid point of AB and E is the mid point of AC.


By Midpoint theorem,





DE = BF |(1)


Similarly in ΔBFD & ΔBCA,



DF = EC = AE |(2)


Similarly in ΔCFE & ΔCBA



EF = AD = DB |(3)


In ΔADE & ΔBDF,


AD = DB |D is mid point


BF = DE |From (1)


DF = EA |From (2)


Thus, ΔADE & ΔBDF are similar to each other by SSS Similarity Rule.


ΔADE~ΔBDF


Similarly,


ΔADE~ΔEFC


ΔDBF~ΔEFC


In ΔADE & ΔDEF,


AD = EF |From (3)


DE = DE


EA = DF |From (2)


ΔADE~ΔDEF


Thus, all the smaller triangles are similar to each other.


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