Two triangles ABC and DBC are formed on the same base BC. If AD and BC intersect each other at O then prove that 

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…(1)
In ΔAOF & ΔDOG,
∠AOF = ∠DOG |vertically opp. angles
∠AFO = ∠DGO |both right angles
ΔAOF~ΔDOF by AA Similarity Rule
…(2)
From (1) & (2),
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Hence, proved.
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