Q6 of 56 Page 135

In a trapezium ABCD, AB || CD and its diagonals meet at point O. If AB = 6 cm and DC = 3 cm then the ratio of the areas of ΔAOB and ΔCOD will be:


In ΔAOB and ΔCOD,


∠O = ∠O |vertically opposite angle


As AB||CD


∠BAO = ∠OCD |alternate ∠s


∠OBA = ∠ODC |alternate ∠s


Thus, ΔAOB~ΔCOD


For two similar triangles, the ratio of their area is equal to the square of the ratio of their corresponding sides.



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