Q3 of 56 Page 135

If figure, if DE || BC, then the value of x will be:

Given,


AD = x + 4


DB = x + 3


AE = 2x – 1


EC = x + 1


In ΔADE & ΔABC,



DE||BC


By BPT,



Putting the values,



(x + 1) = (2x – 1)(x + 3)


⇒ x2 + 5x + 4 = 2x2 + 5x – 3


⇒ x2 + 4 = 2x2 – 3


⇒ x2 = 7


⇒ x = √7

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