The position coordinates of a projectile projected from the ground on a certain planet (with no atmosphere) are given by y = (4t – 2t2) m and x = 3t m where t is in seconds and point of projection is taken as origin the. The angle of projection of projectile with vertical is:-
a) 30° b) 37° c) 45° d) 60°
Given:
...1
x = 3t m ...2
Now, velocity is given by:
..3
Where,
= Velocity component along x – axis
And,
= Velocity component along y – axis
Now, ![]()
So,
= 3 ms–1 ..4
Similarly,
ms–1 ..5
Initial velocity at t = 0 is ![]()
So, putting t = 0 in 4 and 5, we get:
= 3 ms–1 and
= 4 ms–1

Here,
Ɵ = Angle of projection with vertical
So, ![]()
![]()
![]()
Hence Ɵ = 37°
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