Q5 of 43 Page 85

An aeroplane is flying horizontally with a velocity of 600 kmhr–1 and at the height of 1960 m. When it is vertically at a point A on the ground, a bomb is released from it. The bomb strikes the ground at point B. The distance AB is

Aeroplane moves horizontally

Hence horizontal velocity = u = 600 kmhr–1


Height = h = 1960 m


Now, horizontal velocity remains constant as acceleration acts vertically.



For horizontal range AB =


Horizontal Velocity × Time of flight


Let the time of flight = T


Now for, Vertical Motion:


s = h; u = 0; a = g; t = T;


Using equations of motion:





So,


Now, u = 600 kmhr–1 =


So,


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