A particle has displacement 12m east, 5m towards north and 6m vertically upwards. Find the magnitude and sum of these displacements
We first consider displacement due to 12m east and then 5 m north.
, ![]()
Let the resultant displacement be ![]()
Now, ![]()
The angle between east and north direction is 90°
So, ![]()
…1
Now the particle moves vertically upward
. So, we find the resultant due to
and
which are at 90° to each other.
Let the total displacement be d
The,
…2
Now, putting 1 in 2, we get:
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Now, ![]()
So, ![]()
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