A plane surface is inclined making an angle
with the horizontal. From the bottom of this inclined plane bullet is fired with velocity v. The maximum possible range of the bullet on the inclined plane is
Firstly we make the diagram according to the question:
The figure is shown below on the next page

The equation of motion are:
...1
...2
Let the shell fall on the inclined plane at P
Let OP = s
And,
…3
…4
From equation 1 and 3, we get:
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…5
By equating 2 and 4, we get:
…6
Now, putting 5 in 6, we get:
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Using ![]()
Where A =
and B = ![]()
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Now, for max value of R with respect to ![]()
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(Since
has more value)
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So, maximum range along the slope is:
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Now, ![]()
So, ![]()
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