Q13 of 43 Page 85

A particle projected from the ground at angle 45° with horizontal from a distance'd 1' from the foot of a pole, and just after touching the top of the pole it falls on the ground at a distance 'd2' from pole on another side then what is the height of pole?

Firstly we make the diagram according to the question:


Let pole be at O.


The particle is thrown from A and comes back at B after completing its projectile motion.


Now, the angle of projection = 45°


Also, Range of projectile =


Let H be the height of pole =


Using the formula for a maximum height of the projectile () and range of projectile = AB = R =


...1


Where u = initial velocity, and g is acceleration due to gravity.


Also, ...2


Putting R = and Ɵ = 45° in 2, we get:



…3


Now, putting 3 in 1 and and Ɵ = 45°, we get



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