A particle projected from the ground move at 45° with horizontal one second after projection and speed is minimum two seconds after projection. The angle of projection of particle is (neglect air resistance)?
Let: u = Initial Velocity
![]()
![]()
![]()
![]()
At any instantaneous time t:
And ![]()
So, at any time t:
X – Axis:
![]()
…1
Also, ![]()
…2
Y – Axis:
![]()
…3
Also, ![]()
…4
Net speed at time t
![]()
So, ![]()
![]()
![]()
Now, it is given that at t = 2s, v is minimum
Now,
is always constant. Thus v can be minimum only if
= zero.
At t = 2 s ![]()
…5
Given: At t = 1 s ![]()
![]()
![]()
At t = 1 s ![]()
And also, ![]()
So,
…6
Now, putting 5 in 6, we get:
...7
Now, dividing 5 by 7, we get:
![]()
![]()
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.