A projectile is thrown with initial velocity
ms–1. If the range is twice the maximum height then what will be the ans and how?
Given:
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Let, angle made by
with X axis = θ
θ is also known as the angle of projection
...(1)
also, R = range of Projectile
...(2)
H = Maximum height of the projectile
...(3)
Equation
we get
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Also, from (1) ![]()
So, b = 2a
Couldn't generate an explanation.
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