Q9 of 43 Page 85

The ceiling of a hall is 40m high. For maximum horizontal distance, the angle at which the ball may be thrown with speed 56 ms–1 without hitting the ceiling is

Given: u = 56 ms–1;


At the highest point, the vertical component of velocity is zero and is constant throughout the projectile since.


Now, using equations of motion:



So, now for vertical motion at max height:


,


a = –g, ,


s =




Now, from above, Ɵ should be such that,








So, here limiting case is


So, for this limiting case, horizontal range is:



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