Q11 of 43 Page 85

A stone projected from the ground with the certain speed at an angle α with horizontal attains maximum height H1 when it is projected with same speed at an angle α with vertical attains height H2. The horizontal range of a projectile is?

Let u be the initial speed.

At the highest point, the vertical component of velocity is zero.


If α is the angle with horizontal, then


Now, at max height a = –g


Using the equations of motion:





If α is the angle between the vertical,


Now, using the equations of motion:





Now,




Now we know that Horizontal range =



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