A stone is dropped from the window of a bus moving at 60 kmhr–1. If the window is 1.96 m high find the distance along the track which the stone moves before striking the ground.
Horizontal velocity =
= 60 kmhr–1
Height of the window = H = 1.96 m
Horizontal range = ?
Now, we know that:
R = Horizontal Range = Distance along the track stone
makes before striking ground
So,
where T = time of flight
Using equations of motion:
![]()
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Now, for t = T
= g
= H (Vertical Distance)
= 0 (Initial vertical Speed)
So,
![]()

Now,
= 60 kmhr–1 = ![]()
So,
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