Q6 of 319 Page 23

Find the equation of the line which is equidistant from the lines x = –2 and x = 6.

To Find: The equation of the line

Formula Used: The equation of line is [y – y₁ = m(x – x₁)]

Explanation:

Let us plot the lines

Now the line must be at the centre of the lines (–2, 0) and (6, 0).

The Midpoint formula =

Therefore,

Midpoint =

Midpoint = (2, 0)

Hence, the equation of the line is x = 2.

Draw the lines x = – 3, x = 2, y = – 2, y = 3 and write the coordinates of the vertices of the square so formed.

Find the equations of the straight lines which pass through (4, 3) and are respectively parallel and perpendicular to the x–axis.

Find the equation of a line equidistant from the lines y = 10 and y = – 2.

Find the equation of a line making an angle of 150° with the x–axis and cutting off an intercept 2 from y–axis.