Q11 of 319 Page 24

Find the distance of the line 2x + y = 3 from the point ( – 1, – 3) in the direction of the line whose slope is 1.

Given: (x1,y1) = A( – 1, – 3)

And tan θ = 1 ⇒


To find:


The distance of a point from the line in the direction of the line.


Explanation:


So, the equation of the line passing through ( – 1, – 3) and having slope 1 is


Formula Used:


⇒


⇒ x – y = 2


Let x – y = 2 intersect the line 2x + y = 3 at point P.


Let AP = r


Then, the coordinate of P is given by



⇒ x and y


Thus, the coordinate of P is


Clearly, P lies on the line 2x + y = 3



⇒


⇒ 3r


⇒ r


Hence, the distance of the point ( – 1, – 3) from the line 2x + y = 3 is


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