Q7 of 319 Page 23

Find the equation of the perpendicular to the line segment joining (4, 3) and (– 1 1) if it cuts off an intercept – 3 from y – axis.

Given, A line segment joining (4, 3) and (– 1, 1) if it cuts off an intercept – 3 from y–axis.

To Find: The equation of that line.


Formula used: The equation of line is y = mx + C


Explanation: Here, The required equation of line is y = mx + c


Now, c = – 3 (Given)


Let m be slope of given line = – 1


Slope of line joining (x1 – x2) and (y1 – y2) ,


So, Slope of line joining (4, 3) and (– 1, 1) ,


Therefore,


Now, The equation of the line is y = mx + c




2y + 5x + 6 = 0


Hence, The equation of line is 2y + 5x + 6 = 0.


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