Q33 of 319 Page 23

The ratio in which the line 3x + 4y + 2 = 0 divides the distance between the lines 3x + 4y + 5 = 0 and 3x + 4y – 5 = 0 is

The distance between two parallel line 3x + 4y + 5 = 0 and 3x + 4y + 2 = 0 is



The distance between two parallel line 3x + 4y + 2 = 0 and 3x + 4y - 5 = 0 is



Thus required ratio is

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