The distance between the orthocenter and circumcentre of the triangle with vertices (1, 2) (2, 1) and
is
Let A(1, 2), B(2, 1) and C
be the given points.
∴AB![]()
BC
AC
Thus, ABC is an equilateral triangle.
We know that the orthocentre and the circumcentre of an equilateral triangle are same.
So, the distance between the orthocentre and the circumcentre of the triangle
with vertices (1, 2), (2, 1) and
is 0.
Couldn't generate an explanation.
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