Q1 of 319 Page 23

Find the equation to the straight line

cutting off intercepts -5 and 6 from the axes.

Given:


Here, a = -5, b=6


To find:


The equation of line cutoff intercepts from the axes.


Explanation:


So, the equation of the line is


Formula used:



⇒ 6x -5y =-30


Hence, the equation of line cut off intercepts -5 and 6 from the axes is 6x – 5y = -30


More from this chapter

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15

Find the equations of the diagonals of the square formed by the lines x = 0, y = 0, x = 1 and y = 1.

 1

Find the equation to the straight line

cutting off intercepts 3 and 2 from the axes.

 2

Find the equation of the straight line which passes through (1, -2) and cuts off equal intercepts on the axes.

 3

Find the equation to the straight line which passes through the point (5, 6) and has intercepts on the axes

Equal in magnitude and both positive