Q13 of 319 Page 23

Find the equation of the line, which passes through P(1, -7) and meets the axes at A and B respectively so that 4AP – 3BP = 0.

Concept Used:


The equation of the line with intercepts a and b is


Assuming:


The line meets the coordinate axes at A and B, So the coordinates A (a, 0) and B (0, b )


Given:


4AP – 3BP = 0


Explanation:


⇒ AP : BP =3 : 4


Here p= (1, -7)



⇒4a = 7,3b = - 49


⇒a = , b =


Thus the equation of the line is



⇒


⇒ 28x – 3y = 49


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