Find the equation of the straight line which has y-intercept equal to 4/3 and is perpendicular to 3x – 4y + 11 = 0.

Given: equation is perpendicular to 3x – 4y + 11 = 0 and has y-intercept equal to

To find:

The equation of the straight line which has y-intercept equal to and is perpendicular to 3x – 4y + 11 = 0.

Explanation:

The line perpendicular to 3x − 4y + 11 = 0 is 4x + 3y + λ = 0

It is given that the line 4x + 3y + λ = 0 has y – intercept equal to

This means that the line passes through

∴ 0 + 4 + λ = 0

⇒ λ = -4

Substituting the value of λ,

We get 4x + 3y – 4 = 0,

Hence, equation of the required line is 4x + 3y – 4 = 0