Q11 of 319 Page 24

Find the equation of the right bisector of the line segment joining the points (a, b) and (a1, b1).

Given: A (a, b) and B (a1, b1) be the given points


To find:


Equation of the right bisector of the line segment joining the points (a, b) and (a1, b1).


Explanation:


Let C be the midpoint of AB.


∴ coordinates of C


And, slope of AB


So, the slope of the right bisector of AB is


Thus, the equation of the right bisector of the line segment joining the points (a, b) and (a1, b1) is



⇒ 2 (a1-a)x + 2y(b1-b) + (a2 + b2) – (a12 + b12) = 0


Hence, equation of the required line 2 (a1 – a)x + 2y(b1- b) + (a2 + b2) – (a12 + b12) = 0


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