For what value of k does the quadratic equation
4 x2 - 2(k +1) x +(k + 4) = 0 have equal roots? (CBSE 2013)
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For a quadratic equation, ax2 + bx + c = 0,
D = b2 – 4ac
If D = 0, roots are real and equal
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⇒ D = 4(k + 1)2 – 4 × 4(k + 4) = 0
⇒ 4k2 + 8k + 4 – 16k – 64 = 0
⇒ k2 – 2k - 15 = 0
⇒ k2 – 5k + 3k – 15 = 0
⇒ (k – 5)(k + 3) = 0
⇒ k = -3, 5
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