Find the roots of the following quadratic equation:
x2 – 3√5 x + 10 = 0 (CBSE 2011)
Here, on comparing with general equation ax2 + bx + c = 0, we get
a = 1
b = - 3√5
c = 10
Now, Discriminant = D = (b2 – 4ac)
∴ D = [45 – (4 × 1 × 10)]
= [45 - 40]
= 5
Therefore roots of the equation are given by:
x = (-b ± √D)/2a
∴ x = (3√5 ± (√5))/2
= [(4√5)/2] or [2√5/2]
= 2√5 or √5.
Thus the roots of the equation are 2√5 and √5.
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are the roots of the equation
, find the values of a and b. (CBSE 2016)