Solve the following for x: (CBSE 2015)
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⇒ (7x+1)(4x-1) = 29(x2 – 1)
⇒ 28x2 + 4x – 7x – 1 = 29x2 – 29
⇒ 28x2 -3x– 1 = 29x2 – 29
⇒ x2 + 3x – 28 = 0
⇒ x2 + 7x – 4x – 28 = 0
⇒ x( x + 7) – 4 (x + 7) = 0
⇒ (x – 4) ( x + 7) = 0
⇒ x = 4 or -7
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