Solve the following quadratic equation for x:

3√5x² + 25x – 10√5 = 0 (CBSE 2015)

In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized.

⇒ 3√5x² + 30x – 5x – 10√5 = 0

⇒ 3√5x(x + 2√5) – 5(x + 2√5) = 0

⇒ (x + 2√5)(3√5x – 5) = 0

⇒ x = -2√5, √5/3