Q13 of 82 Page 4

For what value of k does the quadratic equation

(k +4) x2 + (k +1) x +1 = 0 have equal roots? (CBSE 2013)

Let D be the discriminant of the given equation.


We have a = k + 4, b = k + 1, c = 1


D = b2 – 4ac


= (k +1)2 – 4(K + 4)(k + 1)


= k2 + 1 + 2k – 4(k2 + k + 4k + 4)


= = k2 + 1 + 2k – 4k2 - 4k - 16k – 16
= k2 – 2k – 15


= k2 – 5K + 3K – 15


= k(k – 5) + 3(k – 5)


= (k – 5) ( k + 3)


If roots are real, then


D = 0


(k – 5)(k + 3) = 0


k = 5,-3


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