Q78 of 82 Page 4

Find x in terms of a, b and c: (CBSE 2016)

We have,



(x – c) [ax + bx – 2ab] = 2c (x2 – bx – ax + ab)


ax2 + bx2 – 2bx – acx – bcx + 2abc = 2cx2 – 2bcx – 2cax + 2abc


ax2 + bx2 – 2cx2 – 2abx + bcx + cax = 0


x2 (a + b – 2c) + x (- 2ab + bc + ca) = 0


∴ x = 0


Or x (a + b – 2c) + (- 2ab + bc + ca) = 0


∴

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