Solve the following for x: (CBSE 2015)
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In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized.
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Taking L.C.M
Cross Multiplying we get,
⇒ 7(2 x2 + 18) = 48(x2 – 9)
⇒ -84x = 48x2 – 432
⇒ 4x2 + 7x – 36 = 0
⇒ 4x2 + 16x – 9x – 36 = 0
⇒ 4x(x + 4) -9(x + 4) = 0
⇒ (4x – 9)(x + 4) = 0
⇒ x = 9/4, -4
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