Solve the following for x: (CBSE 2014)

In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized.

⇒ (5 - x)(3x – 1) = 4x + 4

⇒ -3x² + 16x – 5 = 4x + 4

⇒ 3x² - 12x + 9 = 0

⇒ 3x² – 3x – 9x + 9 = 0

⇒ 3x(x – 1) -9(x – 1) =0

⇒ (3x – 9)(x – 1) = 0

⇒ x = 1, 3