Find the value of tan 22°30’.
[Hint: Let θ = 45°, use 
Let, θ = 45°
As we need to find: tan 22°30’ = tan (θ/2)
∵ ![]()
If somehow, we manage to get sin θ and cos θ in numerator and denominator, our problem will be solved as we know that –
sin θ = cos θ = 1/√2 (for θ = 45°)
As, ![]()
Multiplying
in numerator and denominator, we get –
⇒ ![]()
By applying formula of T-ratios of multiple angles-
sin 2x = 2sin x cos x
cos 2x = 2cos2x – 1 or 1 + cos 2x = 2cos2x
∴ ![]()
⇒ tan 22°30’ = ![]()

![]()
By rationalizing the term, we get-
⇒ tan 22°30’ = ![]()
∴ tan 22°30’ = √2 – 1
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