If cos θ + tan θ = 2 cosec θ, then find the general value of θ.
Correct question: cot θ + tan θ = 2cosecθ
Given,
⇒ ![]()
⇒
{∵ sin2θ + cos2θ = 1}
⇒ 1 = 2 cosec θ sin θ cos θ
⇒ 1 = 2 cos θ {∵ sin θ cosec θ = 1}
⇒ cos θ = 1/2 = cos(π/3)
∵ solution of cos x = cos α is given by
x = 2mπ ± α ∀ m ∈ Z
⇒ θ = 2nπ ± π/3, n ∈ Z
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