Q41 of 76 Page 52

The minimum value of 3 cos x + 4 sin x + 8 is

Let y = 3 cos x + 4 sin x + 8


⇒ y-8 = 3 cos x + 4 sin x


We know that, minimum value of A cos θ +Bsin θ = -√(A2+B2)


⇒ y-8 = - √(32+42) = -√25 = -5


⇒ y = -5+8


= 3

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