If sin θ + cos θ = 1, then the value of sin 2θ is equal to
Given that, sin θ + cos θ = 1
Squaring both sides, we get
⇒ (sin θ + cos θ)2 = 1
⇒ sin2θ + cos2θ + 2sin θ cos θ = 1
⇒ 1 + sin2θ = 1
⇒ sin2θ = 1-1
= 0
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