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3. Trigonometric Functions
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Q56 of 76 Page 52

The value of cos2 48°– sin2 12° is

Given that, cos2 48°– sin2 12° = cos (48° + 12°) cos (48° – 12°)


[∵cos2A – sin2B = cos (A + B) cos (A – B)]


= cos60° cos36°



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3. Trigonometric Functions
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