If for real values of x,
then
Given that, ![]()
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⇒ x2+1 = x cos θ
⇒ x2- cos θx +1 = 0
We know that, b2-4ac ≥ 0
⇒ (-cos θ)2-4×1×1 ≥ 0
⇒ cos2θ -4 ≥ 0
⇒ cos2θ ≥ 4
⇒ cos θ ≥ ± 2
But -1 ≤ cos θ ≤ 1
So, no value of θ is possible
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