Q51 of 76 Page 52

If then the value of (1+ tanα) (1 + tanβ) is

We have,




⇒ tanα + tanβ = 1- tanα. tanβ


⇒ tanα + tanβ + tanα.tanβ = 1


On adding 1 both sides, we get


⇒1+ tanα + tanβ + tanα. tanβ = 1+1


⇒1(1+ tanα) + tanβ (1 + tanα) = 2


⇒ (1+ tanα) (1 + tanβ) = 2

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