If cos (θ + ϕ) = m cos (θ – ϕ), then prove that 
[Hint: Express
and apply Componendo and Dividendo]
Correction required: prove that: ![]()
Given,
cos (θ + ϕ) = m cos (θ – ϕ)
To prove: ![]()
∵ cos (θ + ϕ) = m cos (θ – ϕ)
⇒ ![]()
Applying componendo – dividend, we get
⇒ ![]()
From transformation formula, we know that –
cos(A+B) + cos(A – B) = 2cosAcosB
cos(A – B) – cos(A + B) = 2sinA sinB
⇒ ![]()
⇒
{∵ (cos θ)/(sin θ) = cot θ }
⇒ ![]()
⇒ ![]()
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