Q42 of 76 Page 52

The value of tan 3A – tan 2A –tan A is equal to

tan 3A = tan(2A+A)



⇒ tan 3A(1-tan 2A.tan A) = tan 2A + tan A


⇒ tan 3A-tan 3A.tan 2A.tan A = tan 2A + tan A


⇒ tan 3A- tan 2A - tan A = tan 3A.tan 2A.tan A

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