Show that the point (x, y) given by
and
lies on a circle for all real values of t such that –1 ≤ t ≤1 where a is any given real numbers.
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Squaring both the equations,

Adding both the equations,
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x2+y2= a2
The equation of a circle having centre (h,k), having radius as "r" units, is
(x – h)2 + (y – k)2 = r2
Centre = (0, 0) Radius = a units
Hence proved.
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