Q59 of 63 Page 202

Equation of the hyperbola with eccentricty and foci at (± 2, 0) is


Foci = (±ae, 0) = (±2, 0)


So, after comparing the equations,


ae = 2




b2 = a2 (e2 - 1)




Equation of Hyperbola is


Hence is the required equation.

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