The eccentricity of the hyperbola whose latus rectum is 8 and conjugate axis is equal to half of the distance between the foci is
Length of Latus Rectum = 

b2 = 4a ------- (i)
As, Conjugate axis is equal to half of the distance between the foci,
2b = ae
Squaring the above mentioned equation,
4b2 = a2e2 -------- (ii)
b2 = a2 (1 - e2)
4a = a2 (1 - e2)
4 = a (1 - e2)
-------- (iii)
Putting the value from equation (ii),

a = 20
b2 = 4a = 4 × 20 = 80 {From equation (i)}


Hence, the eccentricity of hyperbola is
.
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