Q41 of 63 Page 202

Fill in the Blanks

The equation of the circle having centre at (3, – 4) and touching the line5x + 12y – 12 = 0 is ______.

Perpendicular Distance between a point (3, -4) & the line 5x +12y – 12 = 0,


Perpendicular Distance (Between a point and line) = , whereas the point is and the line is expressed as ax + by + c = 0



Since, the equation of a circle having centre (h,k), having radius as "r" units, is


(x – h)2 + (y – k)2 = r2





169x2 - 1014x + 1521 + 169y2 + 1352y + 2704 – 2025 = 0


169x2 - 1014x + 1521 + 169y2 + 1352y + 679 = 0


Hence, the required equation is 169x2-1014x + 1521 + 169y2 + 1352y + 679 = 0.


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